MCQ
$\int_0^{2 / 3} \frac{d x}{4+9 x^2}=$
- A$\frac{\pi}{12}$
- ✓$\frac{\pi}{24}$
- C$\frac{\pi}{4}$
- D$0$
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For the following distribution function $F(X)$ of a r.v. $X$
| X | 1 | 2 | 3 | 4 | 5 | 6 |
| F(X) | 0.2 | 0.37 | 0.48 | 0.62 | 0.85 | 1 |
$P(3<X \leq 5)=$