MCQ
$\int_{\,0}^{\,2\pi } {|\sin x|\,dx = } $
  • A
    $0$
  • B
    $1$
  • C
    $2$
  • $4$

Answer

Correct option: D.
$4$
d
(d) $\int_0^{2\pi } {|\sin x|dx = \int_0^\pi {\sin x\,dx + \int_\pi ^{2\pi } { - \sin x\,dx} } } $

$ = [ - \cos x]_0^\pi + [\cos x]_\pi ^{2\pi } = 1 + 1 + 1 + 1 = 4$.

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