MCQ
$\int_{\,0}^{\,2\pi } {|\sin x|\,dx = } $
- A$0$
- B$1$
- C$2$
- ✓$4$
$ = [ - \cos x]_0^\pi + [\cos x]_\pi ^{2\pi } = 1 + 1 + 1 + 1 = 4$.
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Let $F(x)=\int_0^{x^2} f(\sqrt{t}) d t$ for $x \in[0,2]$. If $F^{\prime}(x)=f^{\prime}(x)$ for all $x \in(0,2)$, then $F(2)$ equals