MCQ
$\int_0^{\pi /2} {} (\sin x - \cos x)\log (\sin x + \cos x)\,dx = $
- A$ - 1$
- B$1$
- ✓$0$
- DNone of these
Also as $x = 0$ to $\frac{\pi }{2},t = 1$ to $1$.
Since here limit is $'1$ to $1'$,
therefore the value of integral will be zero,
$\left\{ \because \int_{a}^{a}{f(x)dx=0} \right\}$ .
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$f(x)=(1+|\sin x|)^{\frac{3 a}{\sin x \mid}} ,\quad -\frac{\pi}{4}\,<\,x\,<\,0$
$\quad\quad\quad\quad\quad\quad b ,\quad\quad\quad\quad\quad x=0$
$\quad\quad\quad\quad e^{\cot 4 x / \cot 2 x} ,\quad\quad\quad 0\,<\,x\,<\,\frac{\pi}{4}$
If $\mathrm{f}$ is continuous at $\mathrm{x}=0$, then the value of $6 \mathrm{a}+\mathrm{b}^{2}$ is equal to:
| Column | Maximum of $z$ |
| $A$ | $300$ |
| $B$ | $325$ |