MCQ
$\int\frac{1}{7}\sin\Big(\frac{\text{x}}{7}+10\Big)\text{dx}$ is equal to :
  • A
    $\frac{1}{7}\cos\Big(\frac{\text{x}}{7}+10\Big)\text{C}$
  • B
    $-\frac{1}{7}\cos\Big(\frac{\text{x}}{7}+10\Big)\text{C}$
  • $\cos\Big(\frac{\text{x}}{7}+10\Big)\text{C}$
  • D
    $-7\cos\Big(\frac{\text{x}}{7}+10\Big)\text{C}$

Answer

Correct option: C.
$\cos\Big(\frac{\text{x}}{7}+10\Big)\text{C}$
Let $\text{I}=\int\frac{1}{7}\sin\Big(\frac{\text{x}}{7}+10\Big)\text{dx}$
$=\frac{1}{7}\int\sin\Big(\frac{\text{x}}{7}+10\Big)=\frac{1}{7}\frac{-\cos\Big(\frac{\text{x}}{7}+10\Big)}{\frac{1}{7}}$
$=-\cos\Big(\frac{\text{x}}{7}+10\Big)+\text{C}$

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