Question
$\int\frac{2\text{x}}{(2\text{x}+1)^2}\text{dx}$
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$\sec ^{-1} x+\operatorname{cosec}^{-1} x=\frac{\pi}{2} \ldots[$ for $|x| \geq 1]$
(a) increasing
(b) decreasing.
$\sin \theta=-\frac{1}{2}$