MCQ
Integrate the following functions with respect to $x : \int\frac{\text{dx}}{4\text{x}+5}$
  • $\frac{1}{4}\text{ In }(4\text{x}+5)+\text{c}$
  • B
    $\frac{1}{4}\text{ In }(4\text{x}+5)-\text{c}$
  • C
    $\frac{-1}{4}\text{ In }(4\text{x}+5)-\text{c}$
  • D
    $4\text{ In }(4\text{x}-5)-\text{c}$

Answer

Correct option: A.
$\frac{1}{4}\text{ In }(4\text{x}+5)+\text{c}$
$\int\frac{\text{dx}}{4\text{x}+5}=\frac{1}{4}\int\frac{\text{dx}}{\text{x}}$ where $x = 4x + 5$
$=\frac{1}{4}\text{ In }\text{x}+\text{c}_{1}=\frac{1}{4}\text{ In }(4\text{x}+5)+\text{c}_{2}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Differential coefficient of ${x^3}$ with respect to ${x^2}$ is
$\int {\frac{{{e^{{{\tan }^{ - 1}}\sqrt x }}}}{{\sqrt x  + x\sqrt x }}dx = } $
Let two non-collinear unit vectors $\hat{\mathrm{a}}$ and $\hat{\mathrm{b}}$ form an acute angle. A point $\mathrm{P}$ moves so that at any time $\mathrm{t}$ the position vector $\overline{\mathrm{OP}}$ (where $\mathrm{O}$ is the origin) is given by  $\hat{\mathrm{a}} \cos t+\hat{b} \sin t$. When $\mathrm{P}$ is farthest from origin $O$, let $M$ be the length of $\overline{\mathrm{OP}}$ and $\mathrm{u}$ be the unit vector along $\overline{\mathrm{OP}}$. Then,
If $\theta$ is an acute angle and the vector $(\sin\theta)\hat{\text{i}}+(\cos\theta)\hat{\text{j}}$ is perpendicular to the vector $\hat{\text{i}}-\sqrt{3}\hat{\text{j}},$
Let the vectors $\vec{a}, \vec{b}, \vec{c}$ represent three coterminous edges of a parallelopiped of volume V. Then the volume of the parallelopiped, whose coterminous edges are represented by $\vec{a}, \vec{b}+\vec{c}$ and $\vec{a}+2 \vec{b}+3 \vec{c}$ is equal to $..........\,V$
Let $\mathrm{P}(\alpha, \beta, \gamma)$ be the image of the point $\mathrm{Q}(1,6,4)$ in the line $\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}$. Then $2 \alpha+\beta+\gamma$ is equal to ..............
The curve, with the property that the projection of the ordinate on the normal is constant and has a length equal to $'a',$ is
The solution of ${e^{2x - 3y}}dx + {e^{2y - 3x}}dy = 0$ is
If $I =\frac{2}{\pi} \int_{-\pi / 4}^{\pi / 4} \frac{ dx }{\left(1+ e ^{\sin x}\right)(2-\cos 2 x )}$ then $27 I ^2$ equals. . . . . . . .
If the function $f(x)=\left\{\begin{array}{cc}\frac{72^x-9^x-8^x+1}{\sqrt{2}-\sqrt{1+\cos x}} & , x \neq 0 \\ a \log _e 2 \log _e 3 & , x=0\end{array}\right.$ is continuous at $x=0$, then the value of $a^2$ is equal to