_ 1 2 ^2 1 x ^ 2015 ( x - 1 x )dx is equal to - Vidyadip

MCQ

$\int\limits_{\frac{1}{2}}^2 {\frac{1}{x}{{\tan }^{2015}}\left( {x - \frac{1}{x}} \right)dx} $ is equal to

A
$\frac{1}{2}$
B
$2$
✓
$0$
D
$\frac{1}{2015}$

✓

Answer

Correct option: C.

$0$

c
Put $x = \frac{1}{t}$ we get $I = - I \Rightarrow I =0$

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