MCQ
$\int\limits_0^\infty  {} [2 e^{-x}]\, dx$ where $[x]$ denotes the greatest integer function is
  • A
    $0$
  • $ln\, 2$
  • C
    $e^2$
  • D
    $2/e$

Answer

Correct option: B.
$ln\, 2$
b
for $0 < x < ln\, 2,\, [2e^{-x}] = 1,$ otherwise zero $ \Rightarrow I = \int\limits_0^{\ell n\,2} {} \,dx + \int\limits_{\ell n\,2}^\infty  {} 0 \,dx = ln\, 2$

alternatively, put $e^{-x} = t ; - x = ln\, t ; dx = \frac{1}{t}\,dt$
$\int\limits_0^1 {[2t]\frac{1}{t}dt} $ $-\int\limits_0^1 {[2t]\frac{{dt}}{t}} $ ;

$\int\limits_0^{\frac{1}{2}} {0\,dt} $ $+\int\limits_{\frac{1}{2}}^{\frac{1}{2}} {\frac{{dt}}{t}} $

 $=\left. {\ln \,t} \right]_{\frac{1}{2}}^{\,1}$ 

$= [1] - ln\, \frac{1}{2} = ln\, 2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free