- A$8e^3$
- ✓$8(e^3 -1)$
- C$\sqrt 3 \left( {{e^4} - 1} \right)$
- D$\sqrt 3 \left( {{e^8} - 1} \right)$
$\left.=\int_{0}^{\sqrt{3}} \mathrm{e}^{\mathrm{x}^{2}} 16 \mathrm{x} \mathrm{\,dx}=8 \mathrm{e}^{\mathrm{x}^{2}}\right)_{0}^{\sqrt{3}}=8\left(\mathrm{e}^{3}-1\right)$
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A five-digit number is written down at raddom. The probability that the number is divisible by 5, and no two consecutive digits are identical, is:
$f(x)=\sin x-e^{x} \,\,\,\, \text { if } x \leq 0$
$\quad\quad\quad a+[-x] \,\,\,\, \text { if } 0\,<\,x\,<\,1$
$\quad\quad\quad 2 x-b \,\,\,\,\,\,\,\, \text { if } \geq 1$
where $[\mathrm{x}]$ is the greatest integer less than or equal to $\mathrm{x}$. If $\mathrm{f}$ is continuous on $\mathrm{R}$, then $(\mathrm{a}+\mathrm{b})$ is equal to: