Question
Is nuclear mass density dependent on the mass number? $(\text{Given}: \text{r} = \text{r}_0 \text{A}^{\frac{1}{3}})$

Answer

No, since density $=\frac{\text{Mass}}{\text{Volume}}=\frac{\text{A}}{\frac{4}{3}\pi\text{r}^3}=\frac{\text{A}}{\frac{4}{3}\pi\text{r}^3_0\text{A}}$ is independent of A.

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