Question
Is $x = -3$ a solution of the quadratic equation $2x^2 - 7x + 9 = 0$?
✓
Answer
$2x^2 - 7x + 9 = 0$
For $x = -3$ to be solution of the given quadratic equation it should satisfy the equation
So, substituting $x = 5$ in the given equation, we get
$L.H.S=2(-3)^2 - 7(-3) + 9$
$= 18 + 21 + 9$
$= 48$
$\neq R.H.S$
Hence, $x = -3$ is not a solution of the quadratic equation $2x^2 - 7x + 9 = 0.$
For $x = -3$ to be solution of the given quadratic equation it should satisfy the equation
So, substituting $x = 5$ in the given equation, we get
$L.H.S=2(-3)^2 - 7(-3) + 9$
$= 18 + 21 + 9$
$= 48$
$\neq R.H.S$
Hence, $x = -3$ is not a solution of the quadratic equation $2x^2 - 7x + 9 = 0.$
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