MCQ
Isomers of hexane, based on their branching, can be divided into three distinct classes as shown in the figure. $Image$ The correct order of their boiling point is


- A$I > II > III$
- ✓$III > II > I$
- C$II > III > I$
- D$III > I > II$

Hence $III > II > I$
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(figure) $\xrightarrow[CC{{l}_{4}}]{B{{r}_{2}}}(A)\xrightarrow[(ii)\,NaN{{H}_{2}}]{(i)\,alc.\,KOH}(B)\xrightarrow[(ii)\,C{{H}_{3}}-Cl]{(i)\,NaN{{H}_{2}}}(C)$