MCQ
Isopropyl alcohol on oxidation gives
- ✓Acetone
- BAcetaldehyde
- CEther
- DEthylene
The reaction is as follows:
$CH _3 CH ( OH ) CH _3 \underset{ H ^{+}}{\stackrel{[ O ]}{\longrightarrow}} CH _3 COCH _3$
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$Zn \,|\,ZnSO_4\,(0.01\,M)\,||\,CuSO_4\,(1.0\, M)\,|\,Cu,$
the $emf$ of this Daniell cell is $E_1.$ When the concentration of $ZnSO_4$ is changed to $1.0\, M$ and that of $CuSO_4$ changed to $0.01\, M,$ the $emf$ changes to $E_2.$ Fromthe followings, which one is the relationship between $E_1$ and $E_2$ ? (Given, $RT/F = 0.059$)
${{C}_{6}}{{H}_{5}}OH\xrightarrow{NaOH}(A)$ $\mathop {\xrightarrow{{\;C{O_2}\;\;\;\;\;\;\;\;\;\;\;\;}}}\limits_{140\,^oC,\;(4 - 7\,)} (B)$ $\xrightarrow{{HCl}}(C),$
${H_2}C = CH - CH = C{H_2}\xrightarrow[{0{\,^o}C}]{{HBr}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,}
\end{array}\xrightarrow{{ + 25{\,^o}C}}$ $\begin{array}{*{20}{c}}
{C{H_2}CH = CHC{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
These provide an example of $......1......$ control at low temperature and $......2......$ control at higher temperature
Reason : Zinc forms complex with $CuSO_4$