MCQ
$IUPAC$ name of $C{H_3} - CH = CH - C \equiv CH$ is
- APent $-2-$ en $-4-$ yne
- ✓Pent $-3-$ en $-1-$ yne
- CPent $-3-$ yne $-1-$ en
- DPent $-2-$ yne $-1- $ en
In this case $1^{\text {st }}$ prionity is given to triple bond (Terminals) over double bond and there are $5$ No. af carbons chains. therefore the Name of Compound Should be $3$-pent-$3$-ene-$1$-yne. Hence the Correct option is $c$.
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| $List-I$ | $List-II$ |
| $(A)$ $\Psi_{ MO }=\Psi_{ A }-\Psi_{ B }$ | $(I)$ Dipole moment |
| $(B)$ $\mu=Q \times I$ | $(II)$ Bonding molecular orbital |
| $(C)$ $\frac{N_{b}-N_{a}}{2}$ | $(III)$ Anti-bonding molecualr orbital |
| $(D)$ $\Psi_{ MO }=\Psi_{ A }+\Psi_{ B }$ | $(IV)$ Bond order |