
- ✓$5-$ Bromo $-3-$ chloro hex $1-$ ene
- B$2-$ Bromo $-4-$ chloro hex $-5-$ ene
- C$3-$ Chloro $-5-$ bromo hexene
- D$4-$ Chloro $-2-$ bromo hex $-6-$ ene

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$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr}}A$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr + ROOR}}B$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{NBS}}C$

(Given : $R =8.3 \,J \,K ^{-1}\, mol ^{-1}$ )
$(A)$ The decreasing order of atomic radii of group $13$ elements is $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$.
$(B)$ Down the group $13$ electronegativity decreases from top to bottom.
$(C)$ $\mathrm{Al}$ dissolves in dil. $\mathrm{HCl}$ and liberate $\mathrm{H}_2$ but conc. $\mathrm{HNO}_3$ renders Al passive by forming a protective oxide layer on the surface.
$(D)$ All elements of group 13 exhibits highly stable +1 oxidation state.
$(E)$ Hybridisation of $\mathrm{Al}$ in $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ ion is $\mathrm{sp}^3 \mathrm{~d}^2$.
Choose the correct answer from the options given below: