MCQ
IUPAC name of the compound PhCH2CH2CH2COOH is:
- A3-Phenylpropanoic acid
- B4-Phenylpropanoic acid
- C4-Phenylbutanoic acid
- D4-Phenylpentanoic acid
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$(I)$ Only compounds with chiral centers can be optically active
$(II)$ Absence of elements of symmetry is the reason for a molecule's optical activity
$(II)$ All organic compounds contain carbon & hydrogen
$(IV)$ Different cannonical forms of a molecule represent the actual structures of a molecule which has resonace in it
When $P$ is going to form $PF_5$, then these radial distances are going to become arbitrarily ____,____and ____ respectively