MCQ
$IUPAC$ name of
  • A
    $2,6,6-$ Trimethylbicyclo$[1.1.3]$hept $-2 -$ ene
  • B
    $2,2,6-$ Trimethylbicyclo$[3.1.1]$hept $-5 -$ ene
  • $2,6,6-$ Trimethylbicyclo$[3.1.1]$hept $-2 -$ ene
  • D
    $2,7,7-$ Trimethylbicyclo$[3.1.1]$hept $-2 -$ ene

Answer

Correct option: C.
$2,6,6-$ Trimethylbicyclo$[3.1.1]$hept $-2 -$ ene
c

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Simplest alkyne is represented by
A reaction takes place in three steps with individual rate constant and activation energy,

  Rate constant Activation energy
Step $1$ $k_1$ $E_{a_1} = 180\,kJ /mol$
Step $2$ $k_2$ $E_{a_2} = 80\,kJ /mol$
Step $3$ $k_3$ $E_{a_3} = 50\,kJ /mol$

overall rate constant, $k = {\left( {\frac{{{k_1}{k_2}}}{{{k_3}}}} \right)^{2/3}}$ overall activation energy of the reaction will be ........ $kJ\,mol$

Assume that acetone and water form an ideal solution. If $174\  gm$ of acetone is mixed with $126\  gm$ of $H_2O$ then what could be the vapour pressure of the above solution at $298\ K$ if ${P^0}_{acetone}$ and ${P^0}_{{H_2}O}$ at $298\ K$ are $360\ torr$ and $24\  torr$ respectively ........... $torr$.
$IUPAC$ name of the following compound will be
In a set of reactions $m-$ bromobenzoic acid gave a product $D$ . Identify the product $D$

$\xrightarrow{{SOC{l_2}}}B\xrightarrow{{N{H_3}}}C\xrightarrow[{B{r_2}}]{{NaOH}}D$

$CH_3-NH_2$ $\xrightarrow{{HN{O_2}}}$
The heat change for the following reaction at ${298\,^o}K$ and at constant pressure is $ + 7.3\,kcal$ ${A_2}B(s)\, \to \,2A(s) + 1/2\,{B_2}(g)$, $\Delta H = + 7.3\,kcal$ The heat change at constant volume would be
The types of hybridization present in $1, 2- $butadiene are
The least number of oxyacids are formed by
On passing electric current through molten aluminium chloride, $ 11.2$  litre of $C{l_2}$ is liberated at $NTP$  at anode. The quantity of aluminium deposited at cathode is .............. $\mathrm{g}$ (at. wt. of $Al = 27$)