MCQ
જો $3f\left( x \right) - 2f\left( {\frac{1}{x}} \right) = x,$ તો $f'\left( 2 \right) =\ .............$
  • A
    $\frac{2}{7}$
  • $\frac{1}{2}$
  • C
    $2$
  • D
    $\frac{7}{2}$

Answer

Correct option: B.
$\frac{1}{2}$
$3f\left( x \right) - 2f\left( {\frac{1}{x}} \right) = x \ \ \ ..........(1)$
સમી $(1)$ માં $x =\frac{1}{x}$ લેતા
$3f\left( \frac{1}{x} \right) - 2f(x) = \frac{1}{x} \ \ \ ..........(2)$
સમી $(1)$ અને $(2)$ ને ઉકેલતા .
$2x \ 3f(x)-2f(\frac{1}{x})=x$
$3x \ -2f(x)+3f(\frac{1}{x})=\frac{1}{x}$
$6f(x)-4f(\frac{1}{x})={2}{x}$
$\underline{-6f(x)+9f(\frac{1}{x})=\frac{3}{x}}$
$5f(\frac{1}{x})=2x+\frac{3}{x}$
$f(\frac{1}{x})=\frac{1}{5}\left(2x+\frac{3}{x}\right)$
$f({x})=\frac{1}{5}\left(3x+\frac{2}{x}\right)$
$f'({x})=\frac{1}{5}\left(3-\frac{2}{x^2}\right) \ \ $
$\therefore f'(2)=\frac{1}{2}$

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