MCQ
જો $\mathop {\lim }\limits_{x \to 0} \frac{{\log (3 + x)\, - \log (3 - x)}}{x} = k,\,$ તો $k = . $. .
- A$0$
- B$ - \frac{1}{3}$
- ✓$\frac{2}{3}$
- D$ - \frac{2}{3}$
By $ L-$ Hospital’s rule,
$\mathop {\lim }\limits_{x \to 0} \frac{{\frac{1}{{3 + x}} + \frac{1}{{3 - x}}}}{1} = k$
==> $\frac{2}{3} = k$.
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$\sec \left(\theta+(m-1) \frac{\pi}{6}\right) \sec \left(\theta+\frac{m \pi}{6}\right)=-\frac{8}{\sqrt{3}}$ હોય તો . . .