MCQ
જો ${\sin ^2}\theta = \frac{1}{4},$ તો $\theta $ નો વ્યાપક ઉકેલ મેળવો.
- A$2n\pi \pm {( - 1)^n}\frac{\pi }{6}$
- B$\frac{{n\pi }}{2} \pm {( - 1)^n}\frac{\pi }{6}$
- ✓$n\pi \pm \frac{\pi }{6}$
- D$2n\pi \pm \frac{\pi }{6}$
$\Rightarrow \theta = n\pi \pm \frac{\pi }{6}$.
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