MCQ
જો $x=\frac{1}{3}$ માટે $(1+4x)^8$ ના વિસ્તરણમાં મહતમ પદ
- A1
- B2
- C8
- ✓6
$(1+4x)^8$
અહી $\frac{t_{r+1}}{t_r}\geq1$
$\Rightarrow\frac{8-r+1}{r}\left(\frac{4}{3}\right)\geq1$
$\Rightarrow(9-r)4\geq3r\Rightarrow36\geq7r$
$\Rightarrow r\leq5\frac{1}{7}$
$\therefore6$ ઠુુંં પદ
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