MCQ
$K_2MnO_4$ can be converted into $KMnO_4$ by
- APassing $CO_2$ gas
- BPassing $Cl_2$
- CElectrolytic oxidation
- ✓All of these
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Given $\mathrm{R}=8.31\, \mathrm{~J} \,\mathrm{~K}^{-1} \,\mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$