- AClemmensen's reduction
- BCannizzaro reaction
- CRosenmund's reduction
- ✓Oppenaur's oxidation
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$(a)$ Benzene
$(b)$ Toluene
$(c)$ Chlorobenzene and
$(d)$ Phenol
$\begin{array}{*{20}{l}}
{(u){H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHC{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (v){\mkern 1mu} C{H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHCl{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (w){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} H_2^ + {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (x){\mkern 1mu} H - C \equiv C - H} \\
{(y){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} N{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (z){\mkern 1mu} {{(C{H_3})}_2}C\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{N} N{H_2}}
\end{array}$
$A\xrightarrow{{{K_1}}}B$, activation energy $= Ea_1$
$A\xrightarrow{{{K_2}}}C$, activation energy $= Ea_2$
if $E{a_1} = \frac{{E{a_2}}}{3}$ then the relation between $K_1$ and $K_2$ is
$(A)$ $O$ - $O$ bond lengths are equal.
$(B)$ Thermal decomposition of $O _3$ is endothermic.
$(C)$ $O _3$ is diamagnetic in nature.
$(D)$ $O _3$ has a bent structure.
(First dissociation constant of $H _{2} CO _{3}=4.0 \times 10^{-7}$$\log 2=0.3 ;$ density of the soft $\left.\operatorname{drink}=1\, g\, mL ^{-1}\right)$