Given : l || m and p || q To prove : DABC $\cong$ DCDA Proof : l || m and p || q . . . . [Given] In DABC and DCDA $\angle$BAC = $\angle$DCA . . . . . [Alternate interior angles as AB || DC] Similarly, $\angle$ACB = $\angle$CAD . . . [Alternate interior angles as BC || DA] AC = DA . . . [Common] DABC $\cong$ DCDA [By ASA congruency]
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