MCQ
Laboratory method for the preparation of acetyl chloride is
- ✓$C{H_3}COOH + SOC{l_2} \to C{H_3}COCl$
- B$C{H_3}COOH + PC{l_3} \to C{H_3}COCl$
- C$C{H_3}COONa + PC{l_3} \to C{H_3}COCl$
- DAll of these
✓
Answer
Correct option: A.
$C{H_3}COOH + SOC{l_2} \to C{H_3}COCl$
a
In laboratory it is prepared by $SoCl_2$ because by product $SO _2$ and $HCl$ are gases which can easily escape and reave behind $CH _3 COCl$ as a residue.
In laboratory it is prepared by $SoCl_2$ because by product $SO _2$ and $HCl$ are gases which can easily escape and reave behind $CH _3 COCl$ as a residue.
$CH _3 COOH + SOC _2 \longrightarrow CH _3 COC 1+ HCl + SO _2 \uparrow$
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