- AWater.
- ✓Acetic acid.
- CConc$. \ce{H_2SO_4}$
- DDil$. \ce{H_2SO_4}$
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Statement $I$: Aniline reacts with con. $\mathrm{H}_2 \mathrm{SO}_4$ followed by heating at $453-473 \mathrm{~K}$ gives $\mathrm{p}$ aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement $II$: In Friedel - Craft's alkylation and acylation reactions, aniline forms salt with the $\mathrm{AlCl}_3$ catalyst. Due to this, nitrogen of aniline aquires a positive charge and acts as deactivating group.
In the light of the above statements, choose the correct answer from the options given below :
$C{H_3} - C{H_2} - \mathop S\limits_{ \bullet \,\, \bullet }^{ \bullet \,\, \bullet } - \mathop C\limits^* {H_2} - C{H_2} - Br\xrightarrow{{HOH}}[X]$
$[X]$ will be :
($A$) Formic acid
($B$) Formaldehyde
($C$) Benzaldehyde
($D$) Acetone
Choose the correct answer from the options given below :