MCQ
Least integer in the range of $f(x)$=$\sqrt {(x + 4)(1 - x)} - {\log _2}x$ is
- A$-2$
- B$-1$
- ✓$0$
- D$1$
✓
Answer
Correct option: C.
$0$
c
$f(x)=\sqrt{(x+4)(1-x)}+\log _{1 / 2} x$
$f(x)=\sqrt{(x+4)(1-x)}+\log _{1 / 2} x$
$\because$ $'f'$ is decreasing
minimum value is $f(1)=0.$
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