MCQ
${\left( {2x - \frac{1}{{2{x^2}}}} \right)^{12}}$ ના વિસ્તરણમાં અચળપદ મેળવો.
- A$-7930$
- B$-495$
- C$495$
- ✓$7920$
Hence the required term is $^{12}{C_4}{2^8}{\left( { - \frac{1}{2}} \right)^4} = 7920$.
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