MCQ
${\left[ {Co{{\left( {N{H_3}} \right)}_4}C{l_2}} \right]^ + }$ exhibits
- ✓Geometrical isomerism
- BOptical isomerism
- CBonding isomerism
- DIonisation isomerism

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$(1)$ In gas phase $SO_2$ molecule is $V-$ shape.
$(2)$ In gas Phase $SO_3$ molecule is planar
$(3)$ $\gamma - SO_3$ is cyclic trimer
Which oi the above statement are correct ?
take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
Reason : Dimerisation of benzoic acid.