MCQ
$\left( {\frac{{\sin 2A}}{{1 + \cos 2A}}} \right)\,\left( {\frac{{\cos A}}{{1 + \cos A}}} \right)= $
- ✓$\tan \frac{A}{2}$
- B$\cot \frac{A}{2}$
- C$\sec \frac{A}{2}$
- D${\rm{cosec}}\frac{A}{2}$
$ = \frac{{2\sin A\cos A}}{{2{{\cos }^2}A}}\frac{{\cos A}}{{1 + \cos A}}$
$= \frac{{\sin A}}{{1 + \cos A}} $
$= \tan \frac{A}{2}$.
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