MCQ
$\left| {\begin{array}{*{20}{c}}0&a&{ - b}\\{ - a}&0&c\\b&{ - c}&0\end{array}} \right| = $
  • A
    $ - 2abc$
  • B
    $abc$
  • $0$
  • D
    ${a^2} + {b^2} + {c^2}$

Answer

Correct option: C.
$0$
c
(c)$\left| {\,\begin{array}{*{20}{c}}0&a&{ - b}\\{ - a}&0&c\\b&{ - c}&0\end{array}\,} \right| = 0$ (Since value of determinant of skew-symmetric matrix of odd orders is $0$).

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $f(x) = {\log _a}x$ and $F(x) = {a^x}$, then $F[f(x)]$ is
For $k \in R$, let the solutions of the equation $\cos \left(\sin ^{-1}\left(x \cot \left(\tan ^{-1}\left(\cos \left(\sin ^{-1} x\right)\right)\right)\right)\right)=k, 0\,<\,|x|<\,\frac{1}{\sqrt{2}}$ be $\alpha$ and $\beta$, where the inverse trigonometric functions take only principal values. If the solutions of the equation $x ^{2}- bx -5=0$ are $\frac{1}{\alpha^{2}}+\frac{1}{\beta^{2}}$ and $\frac{\alpha}{\beta}$, then $\frac{b}{k^{2}}$ is equal to$......$
A function $f(x)$ satisfies $f\left( x \right) = f\left( {\frac{c}{x}} \right)$ for some real number $c\left( {c > 1} \right)$ and $\forall\, x > 0$. If $\int\limits_1^{\sqrt c } {\frac{{f\left( x \right)}}{x}} dx = 3$ , then the value of $\int\limits_1^c {\frac{{f\left( x \right)}}{x}} dx$ is
The area of the circle $x^{2}+y^{2}=16$ exterior to the parabola $y^{2}=6 x$ is
The value of $\int_{\,0}^{\,\sqrt 2 } {[{x^2}]\,dx} ,$ where $[.]$ is the greatest integer function
A and B are two events such that P(A) = 0.25 and P(B) = 0.50. The probability pf both happening together is 0.14. The probability of both A and B hot happening is.
How many $3 \times 3$ matrices $\mathrm{M}$ with entries from $\{0,1,2\}$ are there, for which the sum of the diagonal entries of $M^T M$ is $5$ ?
If $a $ and  $b $ are two unit vectors such that $a+2b$ and $5a - 4b$ are perpendicular to each other, then the angle between $a$  and $b $ is ............. $^o$
Let the mean and the standard deviation of the probability distribution

$X$ $\alpha$ $1$ $0$ $-3$
$P(X)$ $\frac{1}{3}$ $K$ $\frac{1}{6}$ $\frac{1}{4}$

be $\mu$ and $\sigma$, respectively. If $\sigma-\mu=2$, then $\sigma+\mu$ is equal to....................

If $\frac{\text{dy}}{\text{dx}}=\text{y}\sin2\text{x},\text{y}(0)=1$ then solution is: