- A${a^3} + {b^3} + {c^3} - 3abc$
- ✓$3abc - {a^3} - {b^3} - {c^3}$
- C${a^3} + {b^3} + {c^3} - {a^2}b - {b^2}c - {c^2}a$
- D$(a+b+c)(a^2+b^2+c^2+ab+bc+ca)$
by ${R_1} \to {R_1} + {R_2} + {R_3}$
$\Delta = (a + b + c)\,.\,\left| {\,\begin{array}{*{20}{c}}2&0&1\\{c + a}&{b - c}&b\\{a + b}&{c - a}&c\end{array}\,} \right|$
On expanding,
$ - (a + b + c)\,({a^2} + {b^2} + {c^2} - ab - bc - ca)$
= $ -(a^3 + b^3 + c^3 - 3abc) = 3abc - a^3 -b^3 - c^3$
Trick : Put $a = 1,\,b = 2,\,c = 3$ and check it.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
($1$) Let $E_1, E_2$ and $F_1 F_2$ be the chords of $S$ passing through the point $P_0(1,1)$ and parallel to the $x$-axis and the $y$-axis, respectively. Let $G _1 G _2$ be the chord of $S$ passing through $P _0$ and having slope -$1$ . Let the tangents to $S$ at $E_1$ and $E_2$ meet at $E_3$, the tangents to $S$ at $F_1$ and $F_2$ meet at $F_3$, and the tangents to $S$ at $G_1$ and $G_2$ meet at $G_3$. Then, the points $E_3, F_3$, and $G _3$ lie on the curve
$(A)$ $x+y=4$ $(B)$ $(x-4)^2+(y-4)^2=16$ $(C)$ $(x-4)(y-4)=4$ $(D)$ $x y=4$
($2$) Let $P$ be a point on the circle $S$ with both coordinates being positive. Let the tangent to $S$ at $P$ intersect the coordinate axes at the points $M$ and $N$. Then, the mid-point of the line segment MN must lie on the curve
$(A)$ $(x+y)^2=3 x y$ $(B)$ $x^{2 / 3}+y^{2 / 3}=2^{4 / 3}$ $(C)$ $x^2+y^2=2 x y$ $(D)$ $x^2+y^2=x^2 y^2$
Give the answer or quetion ($1$) and ($2$)
$(A)$ $16$ $(B)$ $18$ $(C)$ $24$ $(D)$ $22$