MCQ
Let $\mathrm{A}(-1,1)$ and $\mathrm{B}(2,3)$ be two points and $\mathrm{P}$ be a variable point above the line $A B$ such that the area of $\triangle \mathrm{PAB}$ is $10$ . If the locus of $\mathrm{P}$ is $\mathrm{ax}+\mathrm{by}=15$, then $5 a+2 b$ is :
  • $-\frac{12}{5}$
  • B
     $-\frac{6}{5}$
  • C
    $4$
  • D
    $6$

Answer

Correct option: A.
$-\frac{12}{5}$
a
$\frac{1}{2}\left|\begin{array}{lll}\mathrm{h} & \mathrm{k} & 1 \\ -1 & 1 & 1 \\ 2 & 3 & 1\end{array}\right|=10$

$ -2 x+3 y=25 $

$ -\frac{6}{5} x+\frac{9}{5} y=15 $

$ a=-\frac{6}{5}, b=\frac{9}{5} $

$ 5 a=-6,2 b=\frac{18}{5}$

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