MCQ
Let $a, b, c$ be non-zero real numbers such that ; $\int\limits_0^1 {} (1 + cos^8x) (ax^2 + bx + c) dx$ $= \int\limits_0^2 {} (1 + cos^8x) (ax^2 + bx + c) dx$ , then the quadratic equation $ax^2 + bx + c = 0$ has :
  • A
    no root in $(0, 2)$
  • atleast one root in $(0, 2)$
  • C
    a double root in $(0, 2)$
  • D
    none

Answer

Correct option: B.
atleast one root in $(0, 2)$
b
$\int\limits_0^1 {(1 + {{\cos }^8}x)\,\,f(x)\,\,dx} $

$=\int\limits_0^2 {(1 + {{\cos }^8}x)\,\,f(x)\,\,dx} $ 

$=\int\limits_0^1 {(1 + {{\cos }^8}x)\,\,f(x)\,\,dx} \,\, + \,\,\int\limits_1^2 {(1 + {{\cos }^8}x)\,\,f(x)\,\,dx} $
Hence $\,\int\limits_1^2 {(1 + {{\cos }^8}x)\,\,f(x)\,\,dx}  = 0$
  $\Rightarrow (1+cos^8x) f(x) = 0$   at least once in $(1,2)$
but $1 + \cos^8x \neq 0$
$\Rightarrow  f(x) = ax^2 + bx + c$ vanishes at least once in $(1,2)$

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