MCQ
Let a vector $\vec{\text{r}}$ make angles $60^\circ , 30^\circ $ with it and $y-$axes respectively. Find the angle $\vec{\text{r}}$ make with $z-$axis:
  • A
    $30^\circ $
  • B
    $60^\circ $
  • $90^\circ $
  • D
    $120^\circ $

Answer

Correct option: C.
$90^\circ $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $\text{A}=\begin{bmatrix}\text{i}&0\\0&\text{i}\end{bmatrix},\text{n}\in\text{N},$ then $A^{4 n}$ equals :
Consider the function

$f(x)=\frac{\mathrm{P}(\mathrm{x})}{\sin (\mathrm{x}-2)}, \quad \mathrm{x} \neq 2$

$\quad \quad \quad \quad 7, \quad\quad\quad \mathrm{x}=2$

where $P(x)$ is a polynomial such that $P^{\prime \prime}(x)$ is always a constant and $P(3)=9$. If $f(x)$ is continuous at $x=2$, then $P(5)$ is equal to $.....$

The value of $c$ in Rolle's theorem when $f(x) = 2x^3 - 5x^2 - 4x + 3, \text{x}\in\Big[\frac{1}{3},3\Big]$ is:
The general solution of differention eqution of the type $\frac{\text{dx}}{\text{dy}}+\text{P}_{1}\text{x}=\text{Q}_{1}$ is:
Let $3\sin(\text{xy})+4\cos(\text{xy})=5,$ then $\frac{\text{dy}}{\text{dx}}=$
The solution of the differential equation $\frac{{dy}}{{dx}} = \frac{y}{x} + \frac{{\phi \,\left( {\frac{y}{x}} \right)}}{{\phi '\,\left( {\frac{y}{x}} \right)}}$ is
Let $f : S \rightarrow S$ where $S =(0, \infty)$ be a twice differentiable function such that $f ( x +1)= xf ( x )$

If $g: S \rightarrow R$ be defined as $g(x)=\log _{e} f(x),$ then the value of $\mid g "(5)- g "(1) \mid$ is equal to :

If $\int \operatorname{cosec}^5 x d x=\alpha \cot x \operatorname{cosec} x\left(\operatorname{cosec}^2 x+\frac{3}{2}\right)+\beta \log _e\left|\tan \frac{x}{2}\right|+C$ where $\alpha, \beta \in \mathbb{R}$ and $\mathrm{C}$ is constant of integration , then the value of $8(\alpha+\beta)$ equals....................
The area bounded by the curve $4 y^{2}=x^{2}(4-x)(x-2)$ is equal to ...... .
The area bounded by the curves $y = \ln x$, $y = \ln |x|$, $y = \,|\ln x|$ and $y = \,|\ln |x||$ is ......... $sq. \,unit$