MCQ
Let $A=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & \alpha & \beta \\ 0 & \beta & \alpha\end{array}\right]$ and $|2 A|^3=2^{21}$ where $\alpha, \beta \in Z$, Then a value of $\alpha $ is
  • A
    $3$
  • $5$
  • C
    $17$
  • D
    $9$

Answer

Correct option: B.
$5$
b
$ |A|=\alpha^2-\beta^2 $

$ |2 A|^3=2^{21} \Rightarrow|A|=2^4 $

$ \alpha^2-\beta^2=16 $

$ (\alpha+\beta)(\alpha-\beta)=16 \Rightarrow \alpha=4 \text { or } 5$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $y=y(x)$ be the solution of the differential equation $x\left(1-x^{2}\right) \frac{d y}{d x}+\left(3 x^{2} y-y-4 x^{3}\right)=0, x>1$ with $y\,(2)=-2$. Then $y\,(3)$ is equal to
The solution of the differential equation $\frac{{{d^2}y}}{{d{x^2}}} = - \frac{1}{{{x^2}}}$ is
Solve:$\sin { \left( { \tan }^{ -1 }\text{x} \right) } ,\left| \text{x} \right| <1$ is equal to:
  1. $\frac { \text{x} }{ \sqrt { 1-{ \text{x} }^{ 2 } } }$
  2. $\frac { \text{x} }{ \sqrt { 1-{ \text{x} }^{ 2 } } }$
  3. $\frac { \text{x} }{ \sqrt { 1-{ \text{x} }^{ 2 } } }$
  4. $\frac { \text{x} }{ \sqrt { 1+{ \text{x} }^{ 2 } } }$
The region represented by $\left| {x - y} \right| \leq 2$ and $\left| {x + y} \right| \leq 2$ is bounded by a
If points $\text{A}(60\hat{\text{i}}+3\hat{\text{j}}),\ \text{B}(40\hat{\text{i}}-8\hat{\text{j}})$ and $\text{C}(\text{a}\hat{\text{i}}+52\hat{\text{j}})$ are collinear, then a is equal to,
  1. 40
  2. -40
  3. 20
  4. -20
Given that $f (x)$ is continuously differentiable on $a \le x \le b$ where $a < b, f (a) < 0$ and $f (b) > 0$, which of the following are always true ?

$(i)$ $f (x)$ is bounded on $a \le x \le b.$

$(ii)$ The equation $f (x) = 0$ has at least one solution in $a < x < b.$

$(iii)$ The maximum and minimum values of $f (x)$ on $a \le x \le b$ occur at points where $f ' (c) = 0$.

$(iv)$ There is at least one point $c$ with $a < c < b$ where $f ' (c) > 0$.

$(v)$ There is at least one point $d$ with $a < d < b$ where $f ' (c) < 0.$

If the function $f(x)\, = \left\{ {\begin{array}{*{20}{c}}{ - x,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x < 1\,\,\,\,}\\{a + {{\cos }^{ - 1}}(x + b),\,\,\,\,\,\,\,\,\,1 \le x \le 2} \end{array}} \right.$  is differentiable at $x = 1 ,$ then $\frac {a}{b}$ is equal to 
If domain of the function $\log _e\left(\frac{6 x^2+5 x+1}{2 x-1}\right)+\cos ^{-1}\left(\frac{2 x^2-3 x+4}{3 x-5}\right)$ is $(\alpha, \beta) \cup(\gamma, \delta]$, then $18\left(\alpha^2+\beta^2+\gamma^2+\delta^2\right)$ is equal to $....$.
$\int\limits^\text{e}_1\log\text{x}\text{ dx}=$
  1. 1
  2. e - 1
  3. e + 1
  4. 0
If the three points A(1, 6), B(3, −4) and C(x, y) are collinear, then the equation satisfying by x and y is:
  1. 5x + y − 11 = 0
  2. 5x + 13y + 5= 0
  3. 5x − 13y + 5 = 0
  4. 13x − 5y + 5 = 0