$(A)$ $e_1^2+e_2^2=\frac{43}{40}$
$(B)$ $e_1 e_2=\frac{\sqrt{7}}{2 \sqrt{10}}$
$(C)$ $\left|e_1^2-e_2^2\right|=\frac{5}{8}$
$(D)$ $e_1 e_2=\frac{\sqrt{3}}{4}$
- ✓$(A,B)$
- B$(B,D)$
- C$(B,C)$
- D$(A,C)$
$(A)$ $e_1^2+e_2^2=\frac{43}{40}$
$(B)$ $e_1 e_2=\frac{\sqrt{7}}{2 \sqrt{10}}$
$(C)$ $\left|e_1^2-e_2^2\right|=\frac{5}{8}$
$(D)$ $e_1 e_2=\frac{\sqrt{3}}{4}$
Point of contact of $x+y=3$ and circle is (1,2)
Also, general point on $x+y=3$ can be taken as $\left(1 \mp \frac{r}{\sqrt{2}}, 2 \pm \frac{r}{\sqrt{2}}\right)$ where, $r=\frac{2 \sqrt{2}}{3}$
So, required points are $\left(\frac{1}{3}, \frac{8}{3}\right)$ and $\left(\frac{5}{3}, \frac{4}{3}\right)$
Comparing with points of contact of ellipse, $a^2=5, B^2=8$
$b^2=4, A^2=1$
$\therefore e_1 e_2=\frac{\sqrt{7}}{2 \sqrt{10}}$ and $e_1^2+e_2^2=\frac{43}{40}$
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