($A$) $f$ has a local minimum at $x=2$
($B$) fhas a local maximum at $x=2$
($C$) $f^{\prime \prime}(2)>f(2)$
($D$) $f(x)-f^{\prime \prime}(x)=0$ for at least one $x \in \mathbb{R}$
- ✓$A,D$
- B$A,B$
- C$A,C$
- D$A,D,B$
($A$) $f$ has a local minimum at $x=2$
($B$) fhas a local maximum at $x=2$
($C$) $f^{\prime \prime}(2)>f(2)$
($D$) $f(x)-f^{\prime \prime}(x)=0$ for at least one $x \in \mathbb{R}$
$Q =\left( m _5^{12} B- m _6^{12} C \right) c ^2$
$ =\left( m _5^{12} B-\left( m _6^{12} C +\Delta m \right)\right) c ^2$
$ =\left( m _5^{12} B- m _6^{12} C \right) c ^2-\Delta mc ^2$
$ =0.014 \times 931.5-4.041$
$ =9 MeV$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]=0$
$\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]=1$
$\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]=3$
$\big[\vec{\text{b}}\vec{\text{c}}\vec{\text{a}}\big]=1$
$STATEMENT -1$ : The probability that the system of equations has a unique solution is $3 / 8$. and $STATEMENT - 2$: The probability that the system of equations has a solution is $1$ .
