MCQ
Let $f (x) = \frac{{\sin x}}{x}$ , then $\int\limits_0^{\frac{\pi }{2}} {f(x)\,\,f\left( {\frac{\pi }{2} - x} \right)\,dx} =$
- ✓$\frac{2}{\pi }\int\limits_0^\pi {f(x)\,dx} $
- B$\int\limits_0^\pi {f(x)\,dx} $
- C$\pi \,\int\limits_0^\pi {f(x)\,dx} $
- D$\frac{1}{\pi }\,\int\limits_0^\pi {f(x)\,dx} $