MCQ
Let $f(x) = \frac{{x\,\, - \,\,1}}{{2\,{x^2}\,\, - \,\,7x\,\, + \,\,5}}$ . Then :
  • A
    $x\overset{limit}{\rightarrow}1 \,\, f(x) = - \frac{1}{3}$
  • B
    $x\overset{limit}{\rightarrow}0 \,\, f(x) = - \frac{1}{5}$
  • C
    $f(x) \neq 0$
  • All of the above

Answer

Correct option: D.
All of the above
d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The sum of the terms of an infinitely decreasing geometric progression is equal to the greatest value of the function $f (x) = x^3 + 3x -9$ on the interval $[- 2, 3]$ . If the difference between the first and the second term of the progression is equal to $f ' (0)$ then the common ratio of the $G.P$. is
The direction cosines of the line joining $(1, -1, 1)$ and $(-1, 1, 1)$ are:
The value of $\int {{{\sec }^3}x\,\,dx} $ will be
If $\text{S}=\begin{bmatrix}\text{a} & \text{b} \\ \text{c} & \text{d} \end{bmatrix},$ then adj A is:
If A and B are two events such that $\text{P(A)}=\frac{4}{5},$ and $\text{P}(\text{A}\cap\text{B})=\frac{7}{10},$ then P(B|A) =
Let $f(x)=2+\cos x$ for all real $x$.

$STATEMENT -1$ : For each real $\mathrm{t}$, there exists a point $\mathrm{c}$ in $[\mathrm{t}, \mathrm{t}+\pi]$ such that $\mathrm{f}^{\prime}(\mathrm{c})=0$. because

$STATEMENT -2$: $f(t)=f(t+2 \pi)$ for each real $t$.

Can two different vectors have the same magnitude:
The area bounded by the curve $2 x^2+y^2=2$ is :
Let $\text{f(x)=}\begin{cases}\frac{\text{x}-4}{|\text{x}-4|}+\text{a},&\text{if }\text{ x} < 4\\\text{a}+\text{b},&\text{if }\text{ x} =4\\\frac{\text{x}-4}{|\text{x}-4|}+\text{b},&\text{if }\text{ x} > 4\end{cases}$ Then$, f(x)$ is continus at $x = 4$ when:
A biased coin with probability $p,\,\,0 < p < 1,$ of heads is tossed until a head appears for the first time. If the probability that the number of tosses required is even is $\frac{2}{5},$ then $p = $