Question
Let l be the lower class limit of a class-interval in a frequency distribution and m be the mid point of the class. Then, the upper class limit of the class is:
  1. $\text{m}+\frac{\text{l+m}}{2}$
  2. $\text{l}+\frac{\text{m+l}}{2}$
  3. $2\text{m}-1$
  4. $\text{m}-2\text{l}$

Answer

  1. $2\text{m}-1$

Solution:

Given that, the lower class limit of a class-interval is l and the mid-point of the class is m. Let u be the upper class limit of the class-interval.

Therefore, we have

$\text{m}=\frac{\text{l+u}}{2}$

⇒ l + u = 2m

⇒ u = 2m - l

Thus the upper class limit of the class is (2m - l).

Hence, the correct choice is (c).

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