MCQ
Let $\left| {\vec a} \right| = \left| {\vec b} \right| = \left| {\vec a - \vec b} \right| = \,1$ then angle between $\vec a$ and $\vec b$ is
  • A
    $\frac{\pi }{6}$
  • $\frac{\pi }{3}$
  • C
    $\frac{\pi }{4}$
  • D
    $\frac{\pi }{2}$

Answer

Correct option: B.
$\frac{\pi }{3}$
b
$|\overrightarrow a  - \overrightarrow b {|^2} = 1$

$ \Rightarrow |\vec a{|^2} + |\vec b{|^2} - 2\left| {\vec a} \right|\left| {\vec b} \right|\cos \theta  = 1$

$ \Rightarrow  \cos \theta=1 / 2 \Rightarrow \cos \theta=1 / 2 $

$\Rightarrow  \theta=\pi / 3$

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