MCQ
Let n(A) = 28, n(A ∩ B) = 8, n(A ∪ B) = 52, then n(A ∩ B′) =.
- A30
- B32
- C20
- Dnone of these.
Solution:
Given n(A) = 28, n(A ∩ B) = 8.
We have A ∩ B′ = A − A ∩ B.
This give n(A ∩ B′) = n(A) − n(A ∩ B)
or, n(A ∩ B′) = 28 − 8 = 20.
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