Question
Let n(A) = 31, n(B) = 20 and n(A ∩ B) = 6, find: n (A - B).
✓
Answer
n(A) = 31, n(B) = 20 and n(A ∩ B) = 6
We know that,
n(A – B) = n(A) – n(A ∩ B)
n(A - B) = 31 - 6 = 25
We know that,
n(A – B) = n(A) – n(A ∩ B)
n(A - B) = 31 - 6 = 25
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