MCQ
Let $p$ , $q$ , $r$ are three real numbers satisfying $\left[ {p\,\,q\,\,r} \right]\left[ {\begin{array}{*{20}{c}}
  2&p&q \\ 
  { - 3}&q&{ - p + r} \\ 
  {12}&r&{ - q + 3r} 
\end{array}} \right] = \left[ {5\,\,\,b\,\,c} \right]$ , then minimum value of $(b + c)$ is 
  • A
    $\frac{{25}}{{157}}$
  • $\frac{{25}}{{49}}$
  • C
    $\frac{{25 \times 271}}{{{{\left( {49} \right)}^2}}}$
  • D
    $\frac{{25 \times 589}}{{{{\left( {157} \right)}^2}}}$

Answer

Correct option: B.
$\frac{{25}}{{49}}$
b
$2 p-3 q+12 r=5$

$\mathrm{b}=\mathrm{p}^{2}+\mathrm{q}^{2}+\mathrm{r}^{2}$

$c=p q-q p+q r-q r+3 r^{2}=3 r^{2}$

$b+c=p^{2}+q^{2}+4 r^{2}$

use : $(2\hat i - 3\hat j + 6\hat k) \cdot (p\hat i - q\hat j + 2r\hat k) \le \sqrt {{2^2} + {3^2} + {6^2}} \sqrt {{p^2} + {q^2} + 4{r^2}} $

$\frac{{25}}{{49}} \le {p^2} + {q^2} + 4{r^2}$

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