$I.$ $P(x)$ is an even function.
$II.$ $P(x)$ can be expressed as a polynomial in $(2 x-1)^2$
$III.$ $P(x)$ is a polynomial of even degree.
Then,
- Aall are false
- Bonly $I$ and $II$ are true
- ✓only $II$ and $III$ are true
- Dall are true
$I.$ $P(x)$ is an even function.
$II.$ $P(x)$ can be expressed as a polynomial in $(2 x-1)^2$
$III.$ $P(x)$ is a polynomial of even degree.
Then,
We have,
$P\left(\sin ^2 x\right) =P\left(\cos ^2 x\right), x \in\left[0, \frac{\pi}{2}\right)$
$P\left(\sin ^2 x\right) =P\left(1-\sin ^2 x\right)$
$P(x) =P(1-x), x \in[0,1]$
$P^{\prime}(x) =-P^{\prime}(1-x)$
So, $P^{\prime}(x)$ is symmetric about line $x=\frac{1}{2}$
So, $P^{\prime}(x)$ has highest degree is odd. $\Rightarrow P(x)$ has highest degree is even.
Hence, option $(c)$ is correct.
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$f(x)\, = \left\{ {\begin{array}{*{20}{c}}{x\,\sin \,\left( {\frac{1}{x}}\right)\,\,\,\,\,\,\,for\,\, - 1 \le x \le 1\,\,and\,\,x \ne \,0}\\
{0\,\,\,\,\,\,\,\,\,\,\,\,for\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\, = \,0}
\end{array}} \right.$
$g(x)\, = \left\{ {\begin{array}{*{20}{c}}{{x^2}\,\sin \,\left( {\frac{1}{x}} \right)\,\,\,\,\,\,\,for\,\, - 1 \le x \le 1\,\,and\,\,x \ne \,0}\\{0\,\,\,\,\,\,\,\,\,\,\,\,for\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\, = \,0}\end{array}} \right.$ $h (x) = | x |^3$ for $- 1 \le x \le 1$ Which of these functions are differentiable at $x = 0$ ?