- A$\frac{1}{3}$
- B$1$
- ✓$\frac{5}{3}$
- D$\frac{7}{3}$
$=(2 \hat{i}-13 \hat{j}-4 \hat{k}) \times\left(3 \hat{i}+\frac{1}{2} \hat{j}+2 \hat{k}\right)$
$-(6+2) \overrightarrow{ a }=\left|\begin{array}{ccc}\hat{ i } & \hat{ j } & \hat{ k } \\ 2 & -13 & -4 \\ 3 & \frac{1}{2} & 2\end{array}\right|$
$\vec{a}=3 \hat{i}+2 \hat{j}-5 \hat{k}$
Projection of $\vec{a}$ on vector $2 \hat{i}+2 \hat{j}+\hat{k}$ is
$\overrightarrow{ a } \cdot \frac{(2 \hat{ i }+2 \hat{ j }+\hat{ k })}{3}=\frac{5}{3}$
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$h(x)=\left\{\begin{array}{lll}\max & \{f(x), g(x)\} & \text { if } x \leq 0, \\ \min & \{f(x), g(x)\} & \text { if } x > 0 .\end{array}\right.$ The number of points at which $h(x)$ is not differentiable is
$x+y+z=2$
$x+2 y+3 z=5$
$x+3 y+\lambda z=\mu$
has infinitely many solutions are, respectively