MCQ
Let $\vec{C}=\vec{A}+\vec{B}$ then
- A$|\vec{C}|$ is always greater then $|\vec{A}|$
- ✓It is possible to have $|\vec{C}|<|\vec{A}|$ and $|\vec{C}|<\vec{B} \mid$
- C$C$ is always equal to $A+B$
- D$C$ is never equal to $A+B$
✓
Answer
Correct option: B.
It is possible to have $|\vec{C}|<|\vec{A}|$ and $|\vec{C}|<\vec{B} \mid$
(b) $\vec{C}+\vec{A}=\vec{B}$.The value of $C$ lies between $A-B$ and $A+B$$\therefore|\vec{C}|<|\vec{A}| \text { or }|\vec{C}|<|\vec{B}|$
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