MCQ
Let $(x, y, z)$ be points with integer coordinates satisfying the system of homogeneous equations:

$3 x-y-z $$ =0 $, $-3 x+z $$ =0 $, $-3 x+2 y+z $$ =0 .$

Then the number of such points for which $x^2+y^2+z^2 \leq 100$ is

  • A
    $3$
  • B
    $9$
  • C
    $5$
  • $7$

Answer

Correct option: D.
$7$
d
Adding first two equations, we get $y = o$

and substituting $y=0$ in third equation, we get, $z=3 x$

So any point which satisfies given system can be taken as, $(a, o, 3 a )$

Now for this point to lie inside inside a sphere of radius $10$ centered at origin.

$\Rightarrow a ^2+ o ^2+(3 a )^2 < 10^2$

$\Rightarrow a ^2 < 10$

So, possible integral values of a are $-3,-2,-1,0,1,2,3$

Hence, number of such points is $7$ .

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free