LiAl H_4 converts acetic acid into - Vidyadip

MCQ

$LiAl{H_4}$ converts acetic acid into

A
Acetaldehyde
B
Methane
✓
Ethyl alcohol
D
Methyl alcohol

✓

Answer

Correct option: C.

Ethyl alcohol

c
(c)$C{H_3}COOH + 4H\mathop {\xrightarrow{{LiAIH_4}}}\limits C{H_3}C{H_2}OH + {H_2}O$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

An element of $3d-$ transition series shows two oxidation states $x$ and $y,$ differ by two units then

Order of decreasing basic strengths of halides is

At constant temperature, the osmotic pressure of a solution

Which of the following statements is not correct ?

In Which of the following increasing order of splitting energy correct ?

The specific rotation of equilibrium mixture of $\alpha - D-$ glucose and $\beta - D-$ glucose, is ....... $^o$

Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$.

Assertion $A$ : $\left[ CoCl \left( NH _3\right)_5\right]^{2+}$ absorbs at lower wavelength of light with respect to $\left[ Co \left( NH _3\right)_5\left( H _2 O \right)\right]^{3+}$

Reason $R$ : It is because the wavelength of the light absorbed depends on the oxidation state of the metal ion.

In the light of the above statements, choose the correct answer from the options given below :

Assertion : Reaction quotient is defined in the same way as equilbrium constant at any stage of the reaction.
Reason : If $Q_c$ (reaction quotient) $ < K_C$ (equilibrium constant) reaction moves in direction of reactants.

For a first order reaction rate constant is given as $\log_{10}K = 12 - \frac{6\times10^3}{T}$ , then what will be value of temperature if its half life period is $6.93\times10^{-3}\, \min$ .......... $K$

In acidic medium $MnO_4^-$ is converted to $Mn^{2+}$ when acts as an oxidant. The quantity of electricity required to reduce $0.06\, mol$ of $MnO_4^-$ would be ........... $\mathrm{F}$